The magnetic field at the center of the circular loop as shown in figure, when a single wire is bent to form a circular loop and also extends to form straight sections, is
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a
μ0I2R⊙
b
μ0I2R1+1π2⊙
c
μ0I2R1-1π2⊗
d
μ0IR1-1π2⊗
answer is B.
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Detailed Solution
Magnetic field due to 'AB';B→1=μ0I4πRsinπ2-sinπ4⊗=μ0I4πR1-12⊗ Magnetic field due to circular loop, B→2=μ0I2R⊙ Magnetic field due to straight wire BC B→3=μ0I4πRsinπ2+sinπ4⊙=μ0I4πR1+12⊙ B→=B→1+B→2+B→3 =μ0I2R+2μ0I4πR12⊙=μ0I2R1+12π⊙