The magnetic field at the center of the circular loop as shown in figure, when a single wire is bent to form a circular loop and also extends to form straight sections, is

Question

Infinity Learn · Accepted Answer

Magnetic field due to ‘AB’;B→$$1=$$μ$$0I4$$$$π$$Rsin$$π$$$$2$$−$$sin$$$$π$$$$4$$⊗$$=$$μ$$0I4$$$$π$$$$R1$$−$$12$$⊗Magnetic field due to circular loop,  B→$$2=$$μ$$0I2R$$⊙Magnetic field due to straight wire BC,B→$$3=$$μ$$0I4$$$$π$$Rsin$$π$$$$2+$$$$sin$$$$π$$$$4$$⊙$$=$$μ$$0I4$$$$π$$$$R1+12$$⊙ B→$$=B$$→$$1+B$$→$$2+B$$→$$3$$ $$=$$μ$$0I2R+2$$μ$$0I4$$$$π$$$$R12$$⊙$$=$$μ$$0I2R1+12$$π⊙

The magnetic field at the center of the circular loop as shown in figure, when a single wire is bent to form a circular loop and also extends to form straight sections, is

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