First slide

Magnetic field due to a current carrying circular ring

Question

The magnetic field at the center O of the circular portion of the current carrying wire [Fig.]

Moderate

A

$(8 π / 3) \times 10^{- 5} T$
B

$(8 π / 3) \times 10^{- 4} T$
C

$2 π \times 10^{- 5} T$
D

$2 π \times 10^{- 4} T$

Solution

We know that the magnetic induction at centre of circular wire
$\begin{array}{l} B = \frac{μ_{0} ni}{2 R} \\ = \frac{(4 π \times 10^{- 7}) (3 / 4) \times 4}{2 \times (3 \times 10^{- 2})} = 2 π \times 10^{- 5} tesla \end{array}$

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