Questions
The magnetic field at the center O of the circular portion of the current carrying wire [Fig.]
a
(8π/3)×10−5T
b
(8π/3)×10−4T
c
2π×10−5T
d
2π×10−4T
detailed solution
Correct option is C
We know that the magnetic induction at centre of circular wireB=μ0ni2R=4π×10−7(3/4)×42×3×10−2=2π×10−5 teslaTalk to our academic expert!
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