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Questions  

The magnetic field at the centre of a circular current carrying coil of radius R is Bc The magnetic field on its axis at a distance R from the centre is Ba. The value of BcBa will be 

a
2
b
122
c
22
d
12

detailed solution

Correct option is C

BcBa=R2+x2R23/2=R2+R2R23/2=22

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