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The magnetic field at the centre of coil of n turns, bent in the form of a square of side 2l , carrying current i, is

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a

2μ0 niπl

b

2μ0 ni2πl

c

2μ0 ni4πl

d

2μ0 niπl

answer is A.

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Detailed Solution

Magnetic field due to one side of the square at centre OB1 =μ04π . 2isin 450l⇒ B1 = μ04π . 2ilHence, magnetic field at centre due to all sidesB=4 B1 = μ0 2iπlMagnetic field due to n turns,Bnet =nB=μ0 2 niπl = μ0 2 niπl

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