First slide

The bar magnet

Question

The magnetic field at a distance d from a short bar magnet in longitudinal and transverse position are in the ratio

Easy

A

1 : 1
B

1 : 2
C

2 : 1
D

0 : 1

Solution

$\begin{array}{l} B_{longitudinal} = \frac{μ_{0}}{4 π} \times \frac{2 M}{d^{3}} \\ and B_{transverse} = \frac{μ_{0}}{4 π} \times \frac{M}{d^{3}} \\ ∴ B_{longitudinal} : B_{transverse} = 2 : 1 \end{array}$

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