First slide

Magnetic field due to a current carrying circular ring

Question

The magnetic field due to a current canying circular loop of radius 3 cm at a point on the axis at a distance of 4 cm from the centre is 54 μT. What will be its value at the centre of the loop?

Moderate

A

250 μT
B

150 μT
C

125 μT
D

75 μT

Solution

$\begin{array}{l} \frac{B_{center}}{B_{axis}} = {(1 + \frac{x^{2}}{r^{2}})}^{3 / 2} \Rightarrow \frac{B_{center}}{54} = {(1 + {(\frac{4}{3})}^{2})}^{3 / 2} = \frac{125}{27} \\ B_{center} = 250 μT \end{array}$

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