Questions
The magnetic field due to a current carrying circular loop of radius 3 cm at a point on the axis at a distance of 4 cm from the centre is 54T, What will be the value at the centre of the loop
detailed solution
Correct option is A
The magnetic field due to a current carrying circular coil is given byB=μ0nir22r2+x23/2or 54=μ0ni(3)22(9+16)3/2=μ0ni×92×(5)2∴ μ0ni=54×2509=1500Bcentre =μ0ni2r=15002×3=250μTTalk to our academic expert!
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The magnetic field at the centre of a circular current carrying coil of radius The magnetic field on its axis at a distance R from the centre is
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