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Q.

The magnetic field due to a current carrying circular loop of radius 3 cm at a point on the axis at a distance of 4 cm from the centre is 54μT, What will be the value at the centre of the loop

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a

250 μT,

b

150μT

c

125μT

d

75 μT

answer is A.

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Detailed Solution

The magnetic field due to a current carrying circular coil is given byB=μ0nir22r2+x23/2or 54=μ0ni(3)22(9+16)3/2=μ0ni×92×(5)2∴ μ0ni=54×2509=1500Bcentre =μ0ni2r=15002×3=250μT
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The magnetic field due to a current carrying circular loop of radius 3 cm at a point on the axis at a distance of 4 cm from the centre is 54μT, What will be the value at the centre of the loop