Magnetic field due to a long solenoid of cross section 15 cm2 is 200 T. This solenoid crosses a square coil of area 2 m2 at its center such that length of solenoid is parallel to the axis of coil then magnetic flux linked through the square coil is:

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Zero

0.1 Wb

0.2 Wb

0.3 Wb

answer is D.

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Detailed Solution

Magnetic field due to the solenoid is along its length so θ=0∘ ϕ=B.A=200×15×10−4=0.3 Wb

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