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The magnetic field of an electromagnetic wave , obeys the relation in a certain region , is  B=1012sin(5×106t)T, where t is the time . Then the induced  emf, in a 300 turns coil of area 20cm2 oriented perpendicular to the field is

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a
−2×10−5cos(5×106t)V
b
−3×10−6cos(5×106t)V
c
−2.5×10−6cos(5×106t)V
d
−3.3×10−6cos(5×106t)V

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detailed solution

Correct option is B

Induced   emf  : e=−dϕdt=−Nd(BAcosθ)dt ⇒e=-NAdBdt        [Coil is perpendicular to field ∴cosθ = 1] ⇒e=-NAd(Bosinωt)dt ⇒e=−BoANωcosωt ⇒e= −10−12×20×10−4×3×102×5×106cos(5×106t) ⇒e=-3×10-6cos(5×106t)


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