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Q.

A magnetic field of induction 8= 35.34x10-6T is applied on an electron in a direction perpendicular to its motion. Find the time required for the electron to complete one revolution. Assume its mass and charge

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a

1 μs

b

2 μs

c

0.5 μs

d

1.5 μs

answer is A.

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Detailed Solution

Force due to magnetic field = B e vNormal force on electron =mV2r∴ Bev=mv2ror v=BermThe time for one revolution isT=2πrV=2πrmBer=2πmBe=2×3⋅14×9⋅1×10−3135⋅34×10−191⋅6×10−19=1×10−6sec=1μs
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