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Q.

The magnetic field inside a 2mH inductor becomes 0.8 of its maximum value in 20μs when the inductor is joined to battery. Find resistance of the circuit (ln5≈1.609)

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a

160 Ω

b

80 Ω

c

320 Ω

d

240 Ω

answer is A.

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Detailed Solution

i∝B. ∴ current also becomes 0.8 of its maximum value       t=τlogei0i0−icurrent i=i0(1-e-RtL) & τ=LRor 20×10−6=2×10−3Rloge5  =160 Ω
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