First slide

Magnetic field due to a current carrying circular ring

Question

Magnetic field intensity at the centre of coil of 50 turns, radius 0.5 m and carrying a current of 2 A is

Easy

A

$0.5 \times 10^{- 5} T$
B

$1.25 \times 10^{- 4} T$
C

$3 \times 10^{- 5} T$
D

$4 \times 10^{- 5} T$

Solution

$B = \frac{μ_{0} Ni}{2 r} = \frac{4 π \times 10^{- 7} \times 50 \times 2}{2 \times 0 .5} = 1 .25 \times 10^{- 4} T$

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