Questions
The magnetic field at O due to current in the infinite wire forming a loop as shown in figure is
a
μ0I4πd cos ϕ1 + cos ϕ2
b
μ04π Id tan ϕ1 + tan ϕ2
c
μ04π Id sin ϕ1 + sin ϕ2
d
μ04π Id cos ϕ1 + sin ϕ2
detailed solution
Correct option is A
B=μ0I4πd sinθ1 + sinθ2But θ1=900-φ1 and θ2=900 -φ2sin θ1 = sin 900 − ϕ1 = cos ϕ1Similarly sin θ2 = cos ϕ2 .Magnetic field on the axis of a current carrying conductor is zero B=μ0I4πd cos ϕ1 + cos ϕ2Talk to our academic expert!
Similar Questions
ABCD is a square loop made of a uniform conducting wire. The current enters the loop at A and leaves at D. The magnetic field is
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