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Q.

The magnetic field at the origin due to the current flowing in the wire is

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a

-μ0I8πa(i^+k^)

b

μ0I2πa(i^+k^)

c

μ0I8πa(-i^+k^)

d

μ0I4πa2(i^-k^)

answer is C.

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Detailed Solution

BOD=0 BOB=0 BAB=μ0I4πa2cos45°(-i^)+cos45°k^ =μ0I8πa(-i^+k^)
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The magnetic field at the origin due to the current flowing in the wire is