The magnetic field of a plane electromagnetic wave is B→$$=3$$×$$10$$−$$8sin200$$$$π$$$$y+cti^T$$ where $$c=3$$×$$108ms$$−$$1$$ is the speed of light. The corresponding electric field is :

Correct option is 1E→=−9sin200πy+ctk^V/m

Questions

The magnetic field of a plane electromagnetic wave is $\vec{B} = 3 \times 10^{- 8} \sin [200 π (y + c t)] \hat{i} T$ where $c = 3 \times 10^{8} m s^{- 1}$ is the speed of light. The corresponding electric field is :

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E→=−9sin200πy+ctk^V/m

E→=3×10−8sin200πy+ctk^V/m

E→=10−6sin200πy+ctk^V/m

E→=9sin200πy+ctk^V/m

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detailed solution

Correct option is A

E0=B0C ⇒E0=3×10−8×3×108=9 V/m E^ =B^×C^⇒E^ =i^×−j^ =−k^

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The magnetic field of a plane electromagnetic wave is B→=3×10−8sin200πy+cti^T where c=3×108ms−1 is the speed of light. The corresponding electric field is :

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The magnetic field of a plane electromagnetic wave is $\vec{B} = 3 \times 10^{- 8} \sin [200 π (y + c t)] \hat{i} T$ where $c = 3 \times 10^{8} m s^{- 1}$ is the speed of light. The corresponding electric field is :