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Q.

The magnetic field of a plane electromagnetic wave is B→=3×10−8sin200πy+cti^T where c=3×108ms−1  is the speed of light. The corresponding electric field is :

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a

E→=−9sin200πy+ctk^V/m

b

E→=3×10−8sin200πy+ctk^V/m

c

E→=10−6sin200πy+ctk^V/m

d

E→=9sin200πy+ctk^V/m

answer is A.

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Detailed Solution

E0=B0C     ​⇒E0=3×10−8×3×108=9 V/m E^ =B^×C^​⇒E^ =i^×−j^ =−k^
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The magnetic field of a plane electromagnetic wave is B→=3×10−8sin200πy+cti^T where c=3×108ms−1  is the speed of light. The corresponding electric field is :