Questions

The magnetic field in the plane electromagnetic wave is given by

${B}_{z}=2\times {10}^{-7}\mathrm{sin}\left(0.5\times {10}^{3}x+1.5\times {10}^{11}t\right)tesla$

The expression for electric field will be

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a

Ez=302 sin 0.5×103x+1.5×1011tV/m

b

Ez=60 sin 0.5×103x+1.5×1011tV/m

c

Ey=302 sin 0.5×1011x+0.5×103tV/m

d

Ey=60 sin 0.5×103x+1.5×1011tV/m

detailed solution

Correct option is D

Wave is propagating along positive X-axis; magnetic field is directed along Z-axis so electric field must be directed alongk∧×i∧=j∧ along Y-axis.Amplitude of electric fieldE0=B0c=2×10-7×3×108=60 V/m

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