The magnetic field in a plane electromagnetic wave is given by By=2×10−7 sin(0.1×103x + 1.1×1011t)T. Write an expression for the electric field
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a
6sin(0.1×103x+1.1×1011t)V/m
b
60sin(0.1×103x+1.1×1011t)V/m
c
6×103sin(0.1x+1.1t)V/m
d
0.6sin(0.1×103x−1.1×1011t)V/m
answer is B.
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Detailed Solution
Step no 1: Eo=CBo=3×108×2×10−7=60V/mStep no 2:In electromagnetic wave, the electric field is varying sinusoidally with x and ‘t’ perpendicular to the direction of magnetic field as well as the direction of electro magnetic wave. So electric field is varying along Z- directionStep 3: Thus Ez=Eosin(2πλx+2πλt)Ez=60sin(0.1×103x+1.1×1011t)V/m