Questions  

The magnetic field at a point ‘P’ on the axial line of a short bar magnet is 5μT ,due South. Now the magnet is turned through 900 in anti clockwise direction. Then, the magnetic field at the same point ‘P’ would be

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a
2.5μT   due East
b
2.5μT   due West
c
5μT due North
d
2.5μT due North
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detailed solution

Correct option is B

After rotation 2.5µT due west equatorial line B↓2 direction = N to S

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Due to a small magnet, intensity at a distance x in the end on position is 9 gauss. What will be the intensity at a distance x2 on broad side on position?

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