The magnetic field in a region is given by B→=B0xak^. A square loop of side d is placed with its edges along the x and y axes. The loop is moved with a constant velocity v→=voi∧. The emf induced in the loop is:

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B0v0 2 d2a

B0v0d22a

B0v0d2a

answer is C.

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Detailed Solution

ε1=B0x+dav0d ε2=B0xav0d εnet=ε1−ε2=B0v0d2a

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