In a magnetic field of 0.05 T, area of a coil changes from 101 cm2 to 100 cm2 without changing the resistance which is 2 Ω. The amount of charge that flow during this period is

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2.5×10−6 coulomb

2×10-6 coulomb

10−6 coulomb

8×10−6 coulomb

answer is A.

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Detailed Solution

ϕ=B⋅A⇒Change in flux, △φ=B⋅△A=0.05(101−100)10−4 Wb = 5×10−6 Wb Now, charge, △Q=△φR=5×10−62 C=2.5×10−6 C

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