Q.
The magnetic field (in Tesla) at point P due to a straight line segment AB of length 6 cm carrying a current of 5 A (See figure) is p×10−5T. Find value of p. μo=4π×10−7N−A−2
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answer is 1.50.
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Detailed Solution
B=μ04πir(sinα+sinβ) Here r=52−32=4cm⇒α=β=37∘∴ B=10−7×54×10−2×(35+35)=1.5×10−5T
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