Questions
Magnetic fields at two points on the axis of a circular coil at a distance of 0.05 m and 0.2 m from the centre are in the ratio 8:1. The radius of coil is________
detailed solution
Correct option is D
Bp=μ0i2r2r2+x232B0.05=μ0i2×r2r2+(0.05)232……(1)B0.2=μ0i2×r2r2+(0.2)232…..(2)(1)(2)B0.05B0.2=r2+(0.2)2r2+(0.05)232⇒8123=r2+(0.2)2r2+(0.05)2⇒4r2+(0.05)2=r2+(0.2)2⇒3r2=(0.2)2−4×(0.05)2=(0.2)2−(2×0.05)2⇒3r2=(0.2)2−(0.1)2=0.04−0.01⇒r2=0.033=0.01⇒r=0.1mTalk to our academic expert!
Similar Questions
In figure, AB is a non-conducting rod. Equal charges of magnitude q are fixed at various points on the rod as shown. The rod is rotated uniformly about an axis passing through O and perpendicular to its length such that linear speed at the end A or B of the rod is 3 ms-1. Magnetic field at O is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
