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Q.

Magnetic flux linked with a closed circuit of resistance 10 Ω is given by ϕ=5t2-4t+1 weber, when t is time in second. Then induced electric current at t = 0 is

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a

1.2 A

b

0.4 A

c

0.8 A

d

1.4 A

answer is B.

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Detailed Solution

ε=-dϕdt=(4-10t) volt  At t=0, ε=4 volt ∴ At t=0, i=410 volt =0.4 volt.
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