The magnetic flux linked with a coil (in Wb) is given by the equation ϕ = 5t2 + 3t + 16. The magnitude of induced emf in the coil at the fourth second will be

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10 V

33 V

43 V

108 V

answer is C.

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Detailed Solution

The magnitude of induced emf is given by|ε|=dϕBdt=ddt5t2+3t+16|ε|=10t+3+0 at t=4s|ε|=10×4+3|ε|=43V

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