Magnetic flux linked with a copper ring of resistance 10Ω is given by ϕ=(2+3t-4t2) Weber where t is the time in second. Then power dissipated in the ring at t = 1 s is

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4 W

2.5 W

4.5 W

5 W

answer is B.

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Detailed Solution

induced emf, E=-dφdt=(8t-3)volt. At t=1sec, E=(8×1-3)volt =5volt. ∴Power =E2R=(5)210W=2.5 W

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