Questions
The magnetic flux linked with a pure inductor varies with the current (i) flowing through it according to the graph shown in figure. If the current increases at a constant rate of 2 A/s, find the potential difference across the inductor.
detailed solution
Correct option is C
ϕ=Li⇒L=ϕ2=32 Henry∴ Induced potential difference=Ldidt=32×2 volt = 3 volt.Talk to our academic expert!
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