The magnetic induction at the centre O in the figure shown is
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a
μ0i4 1R1−1R2
b
μ0i4 1R1+1R2
c
μ0i4 R1−R2
d
μ0i4 R1+R2
answer is A.
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Detailed Solution
In the following figure, magnetic fields at O due to sections 1, 2, 3 and 4 are considered as B1 , B2, B3 and B4, respectively.B1 = B3 = 0B2 = μ04π. πR1 ⊗B4 = μ04π. πiR2 ⊙As B2 > B4 So Bnet = B2 −B4 ⇒ Bnet = μ0i4 1R1 −1R2 ⊗