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Q.

Magnetic induction at a distance ‘r’ from the axis of a very long current carrying straight wire is B1. Now the wire is bent to form a circular loop of radius ‘r’ as shown in figure. The magnetic induction at the centre of the circular loop is found to be B2. Then  B1B2 is equal to

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a

π−1π

b

3π−1π

c

2ππ−1

d

1π−1

answer is D.

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Detailed Solution

B1=μ0i2πr  and   B2=μ0i2r −μ0i2πr∴   B1B2=μ0i2πrμ0i2r 1−1π  =  1π−1
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Magnetic induction at a distance ‘r’ from the axis of a very long current carrying straight wire is B1. Now the wire is bent to form a circular loop of radius ‘r’ as shown in figure. The magnetic induction at the centre of the circular loop is found to be B2. Then  B1B2 is equal to