Magnetic induction at a distance ‘r’ from the axis of a very long current carrying straight wire is B1. Now the wire is bent to form a circular loop of radius ‘r’ as shown in figure. The magnetic induction at the centre of the circular loop is found to be B2. Then B1B2 is equal to
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a
π−1π
b
3π−1π
c
2ππ−1
d
1π−1
answer is D.
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Detailed Solution
B1=μ0i2πr and B2=μ0i2r −μ0i2πr∴ B1B2=μ0i2πrμ0i2r 1−1π = 1π−1
Magnetic induction at a distance ‘r’ from the axis of a very long current carrying straight wire is B1. Now the wire is bent to form a circular loop of radius ‘r’ as shown in figure. The magnetic induction at the centre of the circular loop is found to be B2. Then B1B2 is equal to