Magnetic induction at a distance ‘r’ from the axis of a very long current carrying straight wire is $$B1$$. Now the wire is bent to form a circular loop of radius ‘r’ as shown in figure. The magnetic induction at the centre of the circular loop is found to be $$B2$$. Then $$B1B2$$ is equal to

Question

Magnetic induction at a distance ‘r’ from the axis of a very long current carrying straight wire is $$B1$$. Now the wire is bent to form a circular loop of radius ‘r’ as shown in figure. The magnetic induction at the centre of the circular loop is found to be $$B2$$. Then  $$B1B2$$ is equal to

Infinity Learn · Accepted Answer

$$B1=$$μ$$0i2$$$$π$$r  and   $$B2=$$μ$$0i2r$$ −μ$$0i2$$$$π$$r∴   $$B1B2=$$μ$$0i2$$$$π$$rμ$$0i2r$$ $$1$$−$$1$$π  $$=$$  $$1$$π−$$1$$

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Magnetic induction at a distance ‘r’ from the axis of a very long current carrying straight wire is B1. Now the wire is bent to form a circular loop of radius ‘r’ as shown in figure. The magnetic induction at the centre of the circular loop is found to be B2. Then B1B2 is equal to

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