Magnetic induction on the surface of a long current carrying wire of radius R is 8 µT. Then magnetic induction at a distance R/4 from the axis of the conductor is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
4 µT
b
3 µT
c
2 µT
d
1 µT
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
On the surface, B1=μoi2πR.At a distance r (r ≤ R) from the axis of the conduction;B2=12πμojrR2 .At r = R/4, B2=μoi2πR2.R4=14μoi2πR=B14=84=2 μT.
Magnetic induction on the surface of a long current carrying wire of radius R is 8 µT. Then magnetic induction at a distance R/4 from the axis of the conductor is