The magnetic moment of the assumed dipole at the earth’s centre is $$7.0$$ ×$$1022Am2$$. The magnetic field B at the geomagnetic poles of the earth is P×$$1014R3$$ (The$$ radius of earth is ‘R’$$), then the value of ‘P ’ $$is__$$

Question

The magnetic moment of the assumed dipole at the earth’s centre is  $$7.0$$ ×$$1022Am2$$. The magnetic field B at the geomagnetic poles of the earth  is P×$$1014R3$$ (The$$ radius of earth is ‘R’$$), then the value of ‘P ’ $$is__$$

Infinity Learn · Accepted Answer

The geomagnetic pole is at the end on position of the earth (axial position) $B = \frac{μ_{0}}{4 π} . \frac{2 M}{d^{3}}$

$g i v e n : d = R \Rightarrow B = \frac{10^{7} \times 2 \times 7 \times 10^{22}}{R^{3}} = \frac{14 \times 10^{15}}{R^{3}}$

Hence,

$\frac{P \times 10^{14}}{R^{3}} = \frac{14 \times 10^{15}}{R^{3}} P = 140.00$

Magnetism

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The magnetic moment of the assumed dipole at the earth’s centre is $7 .0 \times 10^{22} A m^{2}$ . The magnetic field B at the geomagnetic poles of the earth is $\frac{P \times 10^{14}}{R^{3}}$ (The radius of earth is ‘R’), then the value of ‘P ’ is__

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Magnetism

Remember concepts with our Masterclasses.

The magnetic moment of the assumed dipole at the earth’s centre is 7.0 ×1022Am2. The magnetic field B at the geomagnetic poles of the earth is P×1014R3 (The radius of earth is ‘R’), then the value of ‘P ’ is__

The geomagnetic pole is at the end on position of the earth (axial position) B=μ04π.2Md3given : d=R ⇒B=107×2×7×1022R3=14×1015R3Hence, P×1014R3=14×1015R3 P=140.00

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The magnetic moment of the assumed dipole at the earth’s centre is $7 .0 \times 10^{22} A m^{2}$ . The magnetic field B at the geomagnetic poles of the earth is $\frac{P \times 10^{14}}{R^{3}}$ (The radius of earth is ‘R’), then the value of ‘P ’ is__