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The magnetic moment of a bar magnet of length 20 cm is $3.6 \times 10^{- 6} A m^{2}$ . The magnetic length is 90% of its geometric length. Then the pole strength of the magnet (in Am) is

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Correct option is C

Magnetic length=910 × Geometric length ⇒2l=910 ×0.2=0.18 mPole Strength, m =M2l=3.6×10-60.18=2×10-5 Am

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The magnetic moment of a bar magnet of length 20 cm is 3.6×10−6Am2 . The magnetic length is 90% of its geometric length. Then the pole strength of the magnet (in Am) is

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The magnetic moment of a bar magnet of length 20 cm is $3.6 \times 10^{- 6} A m^{2}$ . The magnetic length is 90% of its geometric length. Then the pole strength of the magnet (in Am) is