Questions
A magnetic needle lying parallel to a magnetic field requires W units of work to turn it through . The torque required to maintain the needle in this position will be
detailed solution
Correct option is A
W=MB(cos θ1-cos θ2)=MB(cos 0o-cos 60o)=MB1-12=MB2and τ=MB sinθ=MB sin60o=MB32∴τ=MB23⇒τ=3WTalk to our academic expert!
Similar Questions
A magnet of magnetic moment M is situated with its axis along the direction of a magnetic field of strength B. The work done in rotating it by an angle of will be
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