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A magnetic needle oscillates in horizontal plane with a period T at a place where the angle of dip is 60o. When the same needle is made to oscillate in a vertical plane coinciding with the magnetic meridian, its period will be

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a

T

b

2 T

c

T3

d

T2

answer is C.

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Detailed Solution

We know that T=2πIMBcos⁡θAt magnetic meridian, in the vertical plane∴T′=2πIMBsinθFor angle of dip 60oT'T=cot θ=cot 60=13 T'=T3

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