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A magnetic needle is oscillating in earth’s horizontal field BH with a time period of 0.5 sec. A dip needle of same magnetic dipole moment, mass and geometry oscillator in earth’s vertical field BVwith a time period of 1 sec. Then angle of dip at that place is

a
tan−112
b
tan−12
c
tan−118
d
tan−114

detailed solution

Correct option is D

T1=2πIMBH and T2=2πIMBV∴    T1T2=BVBH=tanδ⇒tanδ=T1T22=0.512=14⇒δ=tan−114

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The values of the apparent angles of dip in two planes at right angles to each other are 30o and 45o. Then the true value of the angle of dip at the place is 


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