The magnetic needle of a V.M.M completes 10 oscillations in 92 seconds. When a small magnet is placed in the magnetic meridian 10cm due north of needle with north pole towards south completes 15 oscillations in 69 seconds. The magnetic moment of magnet ( BH = 0.3G) is
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a
4.5Am2
b
0.45Am2
c
0.75 Am2
d
0.225Am2
answer is C.
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Detailed Solution
T1=9.2S,T2=4.6S and T1T2=B2B1⇒9.24.6=B-BHBH⇒B=5BH=1.5×10-4T⇒Mo4π2Md3=1.5×10-4⇒M=0.75Am2