Q.

The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance

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a

0.138 H

b

138.88 H

c

1.389 H

d

13.89 H

answer is D.

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Detailed Solution

Magnetic potential energy stored in an inductor is given byU=12Li2⇒25×10-3=12×L×60×10-32L=25×2×106×10-33600=50036=13.89H
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