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The magnetic potential at a point of a distance 40 cm from an isolated pole is $10^{- 5} Tm$ . Then Magnetic moment in $A m^{2}$ is

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Correct option is B

Formula: V=μ04πMcosθr2 Given V=10−5Tm r=40cm ⇒ r=0.4m ∴10−5=10−7Mcos0o16×10−2 ⇒M=16Am2

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The magnetic potential at a point of a distance 40 cm from an isolated pole is 10-5Tm. Then Magnetic moment in Am2 is

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The magnetic potential at a point of a distance 40 cm from an isolated pole is $10^{- 5} Tm$ . Then Magnetic moment in $A m^{2}$ is