First slide

Magnetism

Question

The magnetic scalar potential due to a magnetic dipole at a point on its axis situated at a distance of 20cm from its center is found to be $1.2 \times 10^{- 5} T m$ . The magnetic moment of the dipole is

Moderate

A

$2.4 A m^{2}$
B

$4.8 A m^{2}$
C

$3.6 A m^{2}$
D

$6.4 A m^{2}$

Solution

Formula $V = \frac{μ_{0}}{4 π} \frac{M \cos θ}{r^{2}}$
$G i v e n : V = 1.2 \times 10^{- 5} T m, r = 20 c m = 0.2 m, \cos (0^{o}) = 1 [f o r a x i a l p o i n t], M = ? \Rightarrow 1.2 \times 10^{- 5} = 10^{- 7} \times \frac{M}{{(0.2)}^{2}} \Rightarrow M = 4.8 A m^{2}$

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