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The magnetic scalar potential due to a magnetic field at a point on its axis situated at a distance of 20 cm from its center is found to be $1.2 \times 10^{- 5} V$ . Then, the magnetic moment of the dipole is

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Correct option is A

The magnetic potential due to dipole is V=μ04π.M cosθr2Given : V=1.2×10-5 Tm ; θ=00 ; r=0.2 m∴1.2×10−5=10−7M0.22 ⇒M=4.8 Am2 .

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The magnetic scalar potential due to a magnetic field at a point on its axis situated at a distance of 20 cm from its center is found to be 1.2×10−5 V . Then, the magnetic moment of the dipole is

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The magnetic scalar potential due to a magnetic field at a point on its axis situated at a distance of 20 cm from its center is found to be $1.2 \times 10^{- 5} V$ . Then, the magnetic moment of the dipole is