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Questions  

A magnetising field of 1600 A/m produces a magnetic flux of 2.4 x 10-5 Weber in an iron bar of cross section 0.2 cm2. Permeability of the bar is 

a
7.5 x 10-3 T A-1m
b
7.5 x 10-2 T A-1m
c
7.5 x 10-4TA-1m
d
75 x 10-3 TA-1m

detailed solution

Correct option is C

Φ=BAB=ΦA=2.4×10−52×10−5=1.2μ=BH=1.21600=1216000=1216×10−3=0.75×10−3=7.5×10−4

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