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Q.

A magnetising field of 1600 A/m produces a magnetic flux of 2.4 x 10-5 Weber in an iron bar of cross section 0.2 cm2. Permeability of the bar is

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a

7.5 x 10-3 T A-1m

b

7.5 x 10-2 T A-1m

c

7.5 x 10-4TA-1m

d

75 x 10-3 TA-1m

answer is C.

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Detailed Solution

Φ=BAB=ΦA=2.4×10−52×10−5=1.2μ=BH=1.21600=1216000=1216×10−3=0.75×10−3=7.5×10−4
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