First slide

The Electrostatic analog

Question

A magnetized wire of moment 'M' is bent into an arc of a circle subtending an angle 60^oat the center. The new magnetic moment will be

Moderate

A

$\frac{3 M}{π} {Am}^{2}$
B

$\frac{2 M}{π} {Am}^{2}$
C

$\frac{M}{π} {Am}^{2}$
D

$\frac{4 M}{π} {Am}^{2}$

Solution

$\begin{array}{rcl} M' & = & \frac{2 Msin (\frac{θ}{2})}{θ}, θ = 60^{o} \\ M' & = & \frac{2 Msin 30^{0}}{\frac{π}{3}} = \frac{3 M}{π} {Am}^{2} \end{array}$

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