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Questions  

Magnification produced by an astronomical telescope for normal vision is 20. Length of the telescope tube for normal vision is 105cm. Then focal length of the objective is

a
60 cm
b
120 cm
c
100 cm
d
80 cm

detailed solution

Correct option is C

fofe  = 2θ ....(1) and  fo+fe = L = 105 .....(2) Solving,  fe = 5 cm fo = 100 cm

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