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Q.

Magnification produced by an astronomical telescope for normal vision is 20. Length of the telescope tube for normal vision is 105cm. Then focal length of the objective is

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a

60 cm

b

120 cm

c

100 cm

d

80 cm

answer is C.

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Detailed Solution

fofe  = 2θ ....(1) and  fo+fe = L = 105 .....(2) Solving,  fe = 5 cm fo = 100 cm
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