Magnification produced by an astronomical telescope for normal vision is 20. Length of the telescope tube for normal vision is 105cm. Then focal length of the objective is
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a
60 cm
b
120 cm
c
100 cm
d
80 cm
answer is C.
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Detailed Solution
fofe = 2θ ....(1) and fo+fe = L = 105 .....(2) Solving, fe = 5 cm fo = 100 cm