The magnifying power of an astronomical telescope for normal vision is 7 and its tube length is 1.6 m. Then focal lengths of eye piece and objective are
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a
20 cm and 160 cm
b
20 cm and 140 cm
c
15 cm and 105 cm
d
10 cm and 70 cm
answer is B.
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Detailed Solution
for normal vision M=f0fe and L=f0+fe∴L=fe(1+M)⇒fe=L1+M=160(1+7)cm=20 cmand f0=7×20 cm=140 cm