First slide

The optical instruments

Question

The magnifying power of an astronomical telescope for relaxed vision is 16. On adjusting, the distance between the objective and eye lens is 34 cm. Then the focal length of objective and eye lens will be respectively

Moderate

A

17 cm, 17 cm
B

20 cm, 14 cm
C

32 cm, 2 cm
D

30 cm, 4 cm

Solution

$In this case | m | = \frac{f_{o}}{f_{e}} = 5 - - - - - (i) and length of telescope = f_{o} + f_{e} = 36 - - - - (ii)$
$Solving (i) and (ii), we get f_{e} = 6 cm, f_{o} = 30 cm .$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App