The magnifying power of a microscope with an objective of 5 mm focal length is 400. The length of its tube is 20 cm. Then the focal length of the eye-piece is
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a
200 cm
b
160 cm
c
2.5 cm
d
0.1 cm
answer is C.
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Detailed Solution
If nothing is said then it is considered that final image is formed at infinite and m∞=L∞−fo−fe.Df∞fe≃LDf0fe⇒400=20×250.5×fe⇒fe=2.5cm