The magnifying power of a telescope is 9. When it is adjusted for parallel rays, the distance between the objective and the eye-piece is found to be 20 cm. The focal length of the two lenses are

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18 cm, 2 cm

11 cm, 9 cm

10 cm, 10 cm

15 cm, 5 cm

answer is A.

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Detailed Solution

In this case |m|=fofe=5----(i) and length of telescope =f0+fe=36---(ii) Solving (i) and (ii), we get fe=6cm,f0=30cm.

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