The magnitude and direction of the current in the circuit shown will be

Since E1(10V) > E2(4V)So current in the circuit will be clockwise.Applying Kirchhoff's voltage law,−1 ×  i+10−4−2 × i−3i=0 ⇒i=1Aa  to b  via  e∴  Current =VR =10−46 =1.0  ampere