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The magnitude of magnetic field due to a dipole of magnetic moment 3.14 Am2 at a point 1 m away from it in a direction making an angle of 600 with the dipole axis is 72.n×10−8T. Then the value of ‘n ’ is

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answer is 31.4.

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Detailed Solution

The magnitude of the field is B=μ04π.Mr3.1+3cos2θ ⇒B=10−7TmA3.14 Am21 m1+3cos2600 ⇒B=3.14×10−7.1+34⇒B=3.14×10−7.74 ⇒B=723.14×10−7 ⇒B=7231.4×10−8 THence, n=31.4

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