Magnitude of magnetic field (in SI units at the center of a hexagonal shape coil of side 10 cm, 50 turns and carrying current I (Ampere) in units of μ0Iπ is :
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a
503
b
5003
c
2503
d
53
answer is B.
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Detailed Solution
Magnetic field due to one side at center is B=μ0i4πrsinα+sinβ=μ0i4π3a2sin30º+sin30º =μ0i2π3aThere are 6 sides and 50 turns B=6×50×μ0i2π30.1=5003μ0iπ